.76=5t^2

Solution for .76=5t^2 equation:

.76=5t^2

We move all terms to the left:

.76-(5t^2)=0

We add all the numbers together, and all the variables

-5t^2+0.76=0

a = -5; b = 0; c = +0.76;
Δ = b2-4ac
Δ = 02-4·(-5)·0.76
Δ = 15.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{15.2}}{2*-5}=\frac{0-\sqrt{15.2}}{-10}
=-\frac{\sqrt{}}{-10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{15.2}}{2*-5}=\frac{0+\sqrt{15.2}}{-10}
=\frac{\sqrt{}}{-10}
$